can you help me with this solving of systems equation?

Question

x-2y=4
2x-3y=5

can you show me how to do it in elimination and substitution?

Answer 1

Elimination Method:
x-2y=4 .. (1)
2x-3y=5 ..(2)

Multiply (1) by 2, and we get
2x-4y=8 ..(3)
Subtract Equation (3) from (2), we get.
y= -3.
Putting y = -3 in (1), we get.
x-2*(-3)=4
or x+6=4.
or x = -2.

Substitution Method:
x-2y=4 .. (1)
2x-3y=5 ..(2)

From (1) we get x = 4+2y.
Substituting in (2), we get
2*(4+2y) - 3y =5
or 8 + y = 5
or y = -3.
Substituting for y in (1), we get x = -2.

Answer 2

x-2y=4....(1)
2x-3y=5...(2)
(1)*2 gives
2x-4y=8
subtracting (2) from this
y=-3
substituting y=-3 in(1)
x+6=4
x=-2
solution set(-2,-3)

Answer 3

by elimination
x-2y=4,multiply it by 2 u get
2x-4y=8
uve also got
2x-3y=5
so if u subract
(2x-3y)-(2x-4y)=5-8
2x-3y-2x+4y=-3
y=-3
once uve got y u can find x
2x-3y=5
2x(-3*-3)=5
2x+9=5
x=5-9/2
x=-4/2
x=-2
it shud be correct!!