Ok Math fans, here's another challenge for you, a question that came up to my mind.
The first one to answer this correctly, with providing all the procedures of doing it, wins 10 whole points.
So here is the question:
Prove that { the difference between the two diagonals} times {the sum of the two diagonals} of any parallelogram equals to (4ab*cosx).
That is, prove that:
(d+f)(d-f) = (4ab)(cosx)
where d is the long diagonal, and f is the short one.
a and b are the two different sides of the parallelogram, and x is the small angle between those two sides. Assume that the other angle is (180 -x).
After providing the proof, give an example.
So, as said, "survival of the fastest!" Nice quote.
2006-07-21
07:43:41
·
4 answers
·
asked by
Anonymous