Hello Yahoo Answers,
I need some help on the following question.
Calcium Carbonate reacts with hydrochloric acid to release carbon dioxide according to the following equation.
CaCO^3 + 2HCl = CO^2 + H^2O + CaCl^2
Atomic weights Ca = 40.1 , C = 12.0, O = 16.0 , Cl = 35.5 , H = 1.0
a. If 12.5 grams of calcium carbonate are mixed with an excess of acid calculate the moles of CO^2 formed.
b. Calculate the volume of CO^2 ( at STP) produced from the 12.5 grams of Clacium Carbonate.
c.If the 12.5 grams of CaCO^3 had been mixed with a volume of HCl such that the number of moles of HCl was 0.2 moles, calculate the moles of CO^2 formed
Any contribution will be appreciated.
Thankyou
2007-11-06
01:14:55
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3 answers
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asked by
Anonymous