4469.6 g of 10% H2SO4 mixed with 1047 g of 45% KOH and 70 L of water (total volume is ~75L), should give a pH of around 2.....however in real life I get a pH of around 1.5-1.6....what is going on here?
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4469.6 grams of 10% H2SO4 mixed with 1047 grams of 45% KOH and 70 L of water (so total volume is ~75L), calculated should give a pH of around 2.....however in real life I get a pH of around 1.5-1.6....what is going on here????
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The calculations are:
4469.6 grams of 10% H2SO4 = 446.95 g/98g per mole = 4.561 moles of H2SO4, 2 protons per mole = 9.122 moles of H+
1047 grams of 45% KOH = 471.15g/56 g per mole = 8.41 moles of OH-
9.122 – 8.41 = 0.712 moles of protons present
à Final volume of solution is around 75L
0.712/75 = 0.00949 moles of H+ present (per litre)
pH = -log[H+]
pH = 2.02
sure a small difference would occur between theory and the real world, but please, this is a pH calcuation
2007-09-26
04:54:45
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4 answers
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asked by
Anonymous