if you bet 1 dollar on numbers 1 to 35 (35 on table) and leave 3 spots open (36, 0, 00) and you make one dollar every time 1 to 35 falls, you lose 35 dollars if 36, 0, and 00 fall. You can press your bet if you lose the first bet by going to 36 dollars on numbers 1 to 35. If you win, you win 36 dollars on that spin which makes the previous loss made back. If 36, 0, and 00 come twice in a row, you lose 1295 total. Is this a good way to bet against roulette, 35 out of 38 numbers by not losing twice in a row.
2007-12-10
04:58:46
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12 answers
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asked by
Anonymous
in
Gambling