If I have a circle, diameter 10cm, and an equilateral triangleis formed from this diameter, jutting out of the "top" of the circle. what is the area of the two sections cut "off" the circle by the equilateral triangle? In other words, the area of the circle not enclosed by the triangle, and not in the "lower" half of the circle?
If you could explain your solution I would be appreciative. My gut reaction is that the answer is 4.08cm^2.
2006-07-19
15:13:15
·
7 answers
·
asked by
teacher
2
in
Mathematics